June 2 Assignment - Woollcombe Class
I’ll have email and Meet open all day. You need me, or just need to talk, I’m here, or I’ll get back to you as quick as I can.
Now to work!!
If you want to use the Meet for a group let me know or we’ll talk about it at 10.
Add to - Q-DUC - this is the biggie
Time to put in your mind map! (and add to it first, for many of you).
Paper is awesome. Take a pic and insert. This is what I expect most people to use. Adding art, doodles, etc is always great in mind maps.
There’s an add-on in Docs that works really well. It’s complicated, but awesome.
(go Add-ons => Get add-ons => Lucidchart Diagrams. Then fiddle away! You might like it.)
On iPad, there are a bunch of great mind-mapping / brainstorming apps. “Inspiration” is really good.
PE - Own Choice
Art: My Choice Day!
Time lapse. As the day goes on, light changes. Other things change. Flowers open and close. Peas and beans grow (quite a lot). Taking multiple pictures over time can show the changes and teach us a lot about using light!
Pick a view
Use tape or something to mark where your camera is
Take 2-5 shots spread out through the day
Math:
Wow! This one looks really easy. Just figure out what x, y, and z are.
Uhhh, maybe not so simple. This is going to take some paper and a pencil.
Try something and tell me why it DOESN’T work.
Answer at the bottom. The explanation (complicated) is for any parents helping - just so you don’t worry all day!
Learning Cafe Menu:
-Please do 20 minutes of Khan unless you’re doing Mrs. Suderman’s math.
-Typing.com
-Code.org or Makecode Arcade
-Put cool stuff on your Google Site
Catching up:
All the chapters so far: https://www.wizardingworld.com/chapters
Khan - get ahead or catch up
The Xs in the left column produce a 1-digit sum, so X = 1, 2, 3, or 4. But looking at the right column, X is the sum of Y and Z, which are distinct numbers, so the smallest possible value of X is 1 + 2 = 3. So X must be either 3 or 4. That means (looking at the left column again) that Y must be at least 6. But Y and Z are summed in both the center and the right columns, producing different digits. So Y and Z must total at least 11, and that means that a 1 is being carried into the total X + X in the left column, producing a total for that column (and a value for Y) of either 3 + 3 + 1 = 7 or 4 + 4 + 1 = 9.
The fact that we’re carrying a 1 into the center column shows us that X + 1 = Z. We’ve established that X is 3 or 4, so Z must be 4 or 5. So:
X = 3 or 4
Y = 7 or 9
Z = 4 or 5
A bit of trial and error shows that X = 4, Y = 9, Z = 5.
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